Base | Representation |
---|---|
bin | 10100101111000101… |
… | …10010000011000111 |
3 | 1001201211121010111101 |
4 | 22113202302003013 |
5 | 140244344141403 |
6 | 5040354120531 |
7 | 542604640651 |
oct | 122742620307 |
9 | 31654533441 |
10 | 11132412103 |
11 | 47a2a57a8a |
12 | 21a8280147 |
13 | 10854a8cc7 |
14 | 7786db6d1 |
15 | 4524e771d |
hex | 2978b20c7 |
11132412103 has 2 divisors, whose sum is σ = 11132412104. Its totient is φ = 11132412102.
The previous prime is 11132412079. The next prime is 11132412131. The reversal of 11132412103 is 30121423111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11132412103 - 213 = 11132403911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11132415103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566206051 + 5566206052.
It is an arithmetic number, because the mean of its divisors is an integer number (5566206052).
Almost surely, 211132412103 is an apocalyptic number.
11132412103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132412103 is an equidigital number, since it uses as much as digits as its factorization.
11132412103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11132412103 its reverse (30121423111), we get a palindrome (41253835214).
The spelling of 11132412103 in words is "eleven billion, one hundred thirty-two million, four hundred twelve thousand, one hundred three".
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