111240433404332 has 12 divisors (see below), whose sum is σ = 197337481176696. Its totient is φ = 54858295925280.

The previous prime is 111240433404323. The next prime is 111240433404337. The reversal of 111240433404332 is 233404334042111.

It is a junction number, because it is equal to n+sod(n) for n = 111240433404292 and 111240433404301.

It is not an unprimeable number, because it can be changed into a prime (111240433404337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190480193894 + ... + 190480194477.

It is an arithmetic number, because the mean of its divisors is an integer number (16444790098058).

Almost surely, 2^{111240433404332} is an apocalyptic number.

It is an amenable number.

111240433404332 is a deficient number, since it is larger than the sum of its proper divisors (86097047772364).

111240433404332 is a wasteful number, since it uses less digits than its factorization.

111240433404332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 380960388448 (or 380960388446 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 111240433404332 its reverse (233404334042111), we get a palindrome (344644767446443).

The spelling of 111240433404332 in words is "one hundred eleven trillion, two hundred forty billion, four hundred thirty-three million, four hundred four thousand, three hundred thirty-two".