Base | Representation |
---|---|
bin | 1101010000011… |
… | …00111101000000 |
3 | 21202020122121202 |
4 | 12220030331000 |
5 | 211431431422 |
6 | 15011240332 |
7 | 2520126260 |
oct | 650147500 |
9 | 252218552 |
10 | 111202112 |
11 | 5785287a |
12 | 312a90a8 |
13 | 1a066588 |
14 | 10aa97a0 |
15 | 9b68b92 |
hex | 6a0cf40 |
111202112 has 56 divisors (see below), whose sum is σ = 253227840. Its totient is φ = 47462400.
The previous prime is 111202103. The next prime is 111202121. The reversal of 111202112 is 211202111.
It is an interprime number because it is at equal distance from previous prime (111202103) and next prime (111202121).
It is a tau number, because it is divible by the number of its divisors (56).
It is a junction number, because it is equal to n+sod(n) for n = 111202093 and 111202102.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 179339 + ... + 179957.
Almost surely, 2111202112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111202112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (126613920).
111202112 is an abundant number, since it is smaller than the sum of its proper divisors (142025728).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111202112 is an equidigital number, since it uses as much as digits as its factorization.
111202112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1039 (or 1029 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 11.
The square root of 111202112 is about 10545.2412016037. The cubic root of 111202112 is about 480.8810669478.
Adding to 111202112 its reverse (211202111), we get a palindrome (322404223).
Subtracting 111202112 from its reverse (211202111), we obtain a palindrome (99999999).
The spelling of 111202112 in words is "one hundred eleven million, two hundred two thousand, one hundred twelve".
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