Base | Representation |
---|---|
bin | 1010000111010001101011… |
… | …1111001100000000100111 |
3 | 1110101001222111110110221102 |
4 | 2201310122333030000213 |
5 | 2424143003003214343 |
6 | 35352303010310315 |
7 | 2225255005534403 |
oct | 241643277140047 |
9 | 43331874413842 |
10 | 11120123101223 |
11 | 35a8021653884 |
12 | 12b71a288839b |
13 | 628813c7ca86 |
14 | 2a6306da4103 |
15 | 1443d73793b8 |
hex | a1d1afcc027 |
11120123101223 has 2 divisors, whose sum is σ = 11120123101224. Its totient is φ = 11120123101222.
The previous prime is 11120123101211. The next prime is 11120123101259. The reversal of 11120123101223 is 32210132102111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11120123101223 - 240 = 10020611473447 is a prime.
It is a super-2 number, since 2×111201231012232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11120123101195 and 11120123101204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11120123101273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560061550611 + 5560061550612.
It is an arithmetic number, because the mean of its divisors is an integer number (5560061550612).
Almost surely, 211120123101223 is an apocalyptic number.
11120123101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120123101223 is an equidigital number, since it uses as much as digits as its factorization.
11120123101223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11120123101223 its reverse (32210132102111), we get a palindrome (43330255203334).
The spelling of 11120123101223 in words is "eleven trillion, one hundred twenty billion, one hundred twenty-three million, one hundred one thousand, two hundred twenty-three".
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