Base | Representation |
---|---|
bin | 10000001011101000010… |
… | …111011100010111111111 |
3 | 10221022021012020001021120 |
4 | 100023220113130113333 |
5 | 121204334001201030 |
6 | 2210502403402023 |
7 | 143224253142321 |
oct | 20135027342777 |
9 | 3838235201246 |
10 | 1112000022015 |
11 | 399662028163 |
12 | 15b61a683313 |
13 | 80b26c49b0c |
14 | 3bb6d0cd611 |
15 | 1ddd4228010 |
hex | 102e85dc5ff |
1112000022015 has 8 divisors (see below), whose sum is σ = 1779200035248. Its totient is φ = 593066678400.
The previous prime is 1112000021999. The next prime is 1112000022071. The reversal of 1112000022015 is 5102200002111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1112000022015 - 24 = 1112000021999 is a prime.
It is a super-2 number, since 2×11120000220152 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15), and also a Moran number because the ratio is a prime number: 74133334801 = 1112000022015 / (1 + 1 + 1 + 2 + 0 + 0 + 0 + 0 + 2 + 2 + 0 + 1 + 5).
It is a junction number, because it is equal to n+sod(n) for n = 1112000021985 and 1112000022003.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37066667386 + ... + 37066667415.
It is an arithmetic number, because the mean of its divisors is an integer number (222400004406).
Almost surely, 21112000022015 is an apocalyptic number.
1112000022015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1112000022015 is a deficient number, since it is larger than the sum of its proper divisors (667200013233).
1112000022015 is an equidigital number, since it uses as much as digits as its factorization.
1112000022015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74133334809.
The product of its (nonzero) digits is 40, while the sum is 15.
Adding to 1112000022015 its reverse (5102200002111), we get a palindrome (6214200024126).
The spelling of 1112000022015 in words is "one trillion, one hundred twelve billion, twenty-two thousand, fifteen".
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