11112220113 has 4 divisors (see below), whose sum is σ = 14816293488. Its totient is φ = 7408146740.

The previous prime is 11112220111. The next prime is 11112220117. The reversal of 11112220113 is 31102221111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11112220113 - 2¹ = 11112220111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11112220092 and 11112220101.

It is not an unprimeable number, because it can be changed into a prime (11112220111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1852036683 + ... + 1852036688.

It is an arithmetic number, because the mean of its divisors is an integer number (3704073372).

Almost surely, 2^11112220113 is an apocalyptic number.

It is an amenable number.

11112220113 is a deficient number, since it is larger than the sum of its proper divisors (3704073375).

11112220113 is an equidigital number, since it uses as much as digits as its factorization.

11112220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3704073374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11112220113 its reverse (31102221111), we get a palindrome (42214441224).

The spelling of 11112220113 in words is "eleven billion, one hundred twelve million, two hundred twenty thousand, one hundred thirteen".