Base | Representation |
---|---|
bin | 1010000010110011100111… |
… | …1101011001001011011011 |
3 | 1110002201202212221001221221 |
4 | 2200230321331121023123 |
5 | 2421413221312010433 |
6 | 35253123130512511 |
7 | 2216566044234460 |
oct | 240547175311333 |
9 | 43081685831857 |
10 | 11043333313243 |
11 | 35784a6835590 |
12 | 12a4331b95737 |
13 | 6214c6c509ca |
14 | 2a2700711667 |
15 | 1423e0b2472d |
hex | a0b39f592db |
11043333313243 has 16 divisors (see below), whose sum is σ = 13809907802880. Its totient is φ = 8579197202400.
The previous prime is 11043333313163. The next prime is 11043333313247. The reversal of 11043333313243 is 34231333334011.
It is not a de Polignac number, because 11043333313243 - 221 = 11043331216091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11043333313199 and 11043333313208.
It is not an unprimeable number, because it can be changed into a prime (11043333313247) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216620908 + ... + 216671881.
It is an arithmetic number, because the mean of its divisors is an integer number (863119237680).
Almost surely, 211043333313243 is an apocalyptic number.
11043333313243 is a deficient number, since it is larger than the sum of its proper divisors (2766574489637).
11043333313243 is a wasteful number, since it uses less digits than its factorization.
11043333313243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433293138.
The product of its (nonzero) digits is 69984, while the sum is 34.
Adding to 11043333313243 its reverse (34231333334011), we get a palindrome (45274666647254).
The spelling of 11043333313243 in words is "eleven trillion, forty-three billion, three hundred thirty-three million, three hundred thirteen thousand, two hundred forty-three".
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