11013021330433 has 4 divisors (see below), whose sum is σ = 11013071130180. Its totient is φ = 11012971530688.

The previous prime is 11013021330319. The next prime is 11013021330527. The reversal of 11013021330433 is 33403312031011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4450699070224 + 6562322260209 = 2109668^2 + 2561703^2 .

It is a cyclic number.

It is not a de Polignac number, because 11013021330433 - 2¹³ = 11013021322241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11013021330398 and 11013021330407.

It is not an unprimeable number, because it can be changed into a prime (11013021310433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24566668 + ... + 25010941.

It is an arithmetic number, because the mean of its divisors is an integer number (2753267782545).

Almost surely, 2^{11013021330433} is an apocalyptic number.

It is an amenable number.

11013021330433 is a deficient number, since it is larger than the sum of its proper divisors (49799747).

11013021330433 is an equidigital number, since it uses as much as digits as its factorization.

11013021330433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49799746.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11013021330433 its reverse (33403312031011), we get a palindrome (44416333361444).

The spelling of 11013021330433 in words is "eleven trillion, thirteen billion, twenty-one million, three hundred thirty thousand, four hundred thirty-three".