Base | Representation |
---|---|
bin | 1010000000111111010011… |
… | …1010010111010010101111 |
3 | 1102222202011212222112001111 |
4 | 2200033310322113102233 |
5 | 2420410300142320421 |
6 | 35230521001252451 |
7 | 2214412232412052 |
oct | 240176472272257 |
9 | 42882155875044 |
10 | 11012110120111 |
11 | 3566234094441 |
12 | 129a279494127 |
13 | 61b58c3337b9 |
14 | 2a0dbba5aa99 |
15 | 1416b492cee1 |
hex | a03f4e974af |
11012110120111 has 2 divisors, whose sum is σ = 11012110120112. Its totient is φ = 11012110120110.
The previous prime is 11012110120091. The next prime is 11012110120147. The reversal of 11012110120111 is 11102101121011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012110120111 - 217 = 11012109989039 is a prime.
It is a super-2 number, since 2×110121101201112 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11012110120091 and 11012110120100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012110190111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506055060055 + 5506055060056.
It is an arithmetic number, because the mean of its divisors is an integer number (5506055060056).
Almost surely, 211012110120111 is an apocalyptic number.
11012110120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012110120111 is an equidigital number, since it uses as much as digits as its factorization.
11012110120111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 11012110120111 its reverse (11102101121011), we get a palindrome (22114211241122).
The spelling of 11012110120111 in words is "eleven trillion, twelve billion, one hundred ten million, one hundred twenty thousand, one hundred eleven".
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