Base | Representation |
---|---|
bin | 11001000010010100000001… |
… | …011001011000110011111001 |
3 | 112102212102102012010021200121 |
4 | 121002110001121120303321 |
5 | 103413020441044444433 |
6 | 1030103514232533241 |
7 | 32123122632212302 |
oct | 3102240131306371 |
9 | 472772365107617 |
10 | 110110099999993 |
11 | 320a2481981825 |
12 | 104240a9851221 |
13 | 4959451411b52 |
14 | 1d295005157a9 |
15 | cae33a4aec2d |
hex | 642501658cf9 |
110110099999993 has 2 divisors, whose sum is σ = 110110099999994. Its totient is φ = 110110099999992.
The previous prime is 110110099999937. The next prime is 110110100000009. The reversal of 110110099999993 is 399999990011011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80213733388944 + 29896366611049 = 8956212^2 + 5467757^2 .
It is a cyclic number.
It is not a de Polignac number, because 110110099999993 - 221 = 110110097902841 is a prime.
It is not a weakly prime, because it can be changed into another prime (110110099999903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055049999996 + 55055049999997.
It is an arithmetic number, because the mean of its divisors is an integer number (55055049999997).
Almost surely, 2110110099999993 is an apocalyptic number.
It is an amenable number.
110110099999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
110110099999993 is an equidigital number, since it uses as much as digits as its factorization.
110110099999993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14348907, while the sum is 70.
The spelling of 110110099999993 in words is "one hundred ten trillion, one hundred ten billion, ninety-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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