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110040311133 = 336551622129
BaseRepresentation
bin110011001111011101…
…0011110010101011101
3101112000220020222212000
41212132322132111131
53300330304424013
6122315105432513
710643621132424
oct1463672362535
9345026228760
10110040311133
11427389834a5
12193b033b739
13a4b897224c
14547c6b82bb
152ce090b973
hex199ee9e55d

110040311133 has 16 divisors (see below), whose sum is σ = 163047830400. Its totient is φ = 73348891200.

The previous prime is 110040311113. The next prime is 110040311159. The reversal of 110040311133 is 331113040011.

It is a de Polignac number, because none of the positive numbers 2k-110040311133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110040311113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 134188 + ... + 487941.

It is an arithmetic number, because the mean of its divisors is an integer number (10190489400).

Almost surely, 2110040311133 is an apocalyptic number.

It is an amenable number.

110040311133 is a deficient number, since it is larger than the sum of its proper divisors (53007519267).

110040311133 is an equidigital number, since it uses as much as digits as its factorization.

110040311133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 628689 (or 628683 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 110040311133 its reverse (331113040011), we get a palindrome (441153351144).

The spelling of 110040311133 in words is "one hundred ten billion, forty million, three hundred eleven thousand, one hundred thirty-three".

Divisors: 1 3 9 27 6551 19653 58959 176877 622129 1866387 5599161 16797483 4075567079 12226701237 36680103711 110040311133