1100201320031 has 4 divisors (see below), whose sum is σ = 1200219621864. Its totient is φ = 1000183018200.

The previous prime is 1100201320013. The next prime is 1100201320033. The reversal of 1100201320031 is 1300231020011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100201320031 - 2⁶ = 1100201319967 is a prime.

It is a super-2 number, since 2×1100201320031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100201319988 and 1100201320015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100201320033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50009150900 + ... + 50009150921.

It is an arithmetic number, because the mean of its divisors is an integer number (300054905466).

Almost surely, 2^{1100201320031} is an apocalyptic number.

1100201320031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1100201320031 is a deficient number, since it is larger than the sum of its proper divisors (100018301833).

1100201320031 is a wasteful number, since it uses less digits than its factorization.

1100201320031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100018301832.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1100201320031 its reverse (1300231020011), we get a palindrome (2400432340042).

The spelling of 1100201320031 in words is "one trillion, one hundred billion, two hundred one million, three hundred twenty thousand, thirty-one".