Base | Representation |
---|---|
bin | 11001000000110111110101… |
… | …001000111001000000110001 |
3 | 112102111221220102011101120211 |
4 | 121000313311020321000301 |
5 | 103404410223141213131 |
6 | 1025550223431504121 |
7 | 32113016602024642 |
oct | 3100676510710061 |
9 | 472457812141524 |
10 | 110011110101041 |
11 | 320644a4739586 |
12 | 10408a82228041 |
13 | 4950006c68146 |
14 | 1d247cd6b16c9 |
15 | cab994c9e5b1 |
hex | 640df5239031 |
110011110101041 has 2 divisors, whose sum is σ = 110011110101042. Its totient is φ = 110011110101040.
The previous prime is 110011110101027. The next prime is 110011110101083. The reversal of 110011110101041 is 140101011110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96608159813025 + 13402950288016 = 9828945^2 + 3661004^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110011110101041 is a prime.
It is not a weakly prime, because it can be changed into another prime (110011110111041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005555050520 + 55005555050521.
It is an arithmetic number, because the mean of its divisors is an integer number (55005555050521).
Almost surely, 2110011110101041 is an apocalyptic number.
It is an amenable number.
110011110101041 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011110101041 is an equidigital number, since it uses as much as digits as its factorization.
110011110101041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 110011110101041 its reverse (140101011110011), we get a palindrome (250112121211052).
The spelling of 110011110101041 in words is "one hundred ten trillion, eleven billion, one hundred ten million, one hundred one thousand, forty-one".
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