Base | Representation |
---|---|
bin | 10100011111011011… |
… | …11001111001000011 |
3 | 1001101200112021222121 |
4 | 22033231321321003 |
5 | 140012241010313 |
6 | 5015343545111 |
7 | 536421615145 |
oct | 121755717103 |
9 | 31350467877 |
10 | 11001110083 |
11 | 4735926917 |
12 | 21702bb197 |
13 | 10642259c2 |
14 | 7650bcc95 |
15 | 445c0d28d |
hex | 28fb79e43 |
11001110083 has 2 divisors, whose sum is σ = 11001110084. Its totient is φ = 11001110082.
The previous prime is 11001110077. The next prime is 11001110129. The reversal of 11001110083 is 38001110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001110083 - 25 = 11001110051 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001110033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555041 + 5500555042.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555042).
Almost surely, 211001110083 is an apocalyptic number.
11001110083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001110083 is an equidigital number, since it uses as much as digits as its factorization.
11001110083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 11001110083 its reverse (38001110011), we get a palindrome (49002220094).
The spelling of 11001110083 in words is "eleven billion, one million, one hundred ten thousand, eighty-three".
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