Base | Representation |
---|---|
bin | 10100011111011011… |
… | …00100001100100001 |
3 | 1001101200100210002021 |
4 | 22033231210030201 |
5 | 140012230134332 |
6 | 5015342021441 |
7 | 536421065104 |
oct | 121755441441 |
9 | 31350323067 |
10 | 11001021217 |
11 | 473587607a |
12 | 2170277881 |
13 | 10641c4414 |
14 | 76509873b |
15 | 445be1c97 |
hex | 28fb64321 |
11001021217 has 2 divisors, whose sum is σ = 11001021218. Its totient is φ = 11001021216.
The previous prime is 11001021197. The next prime is 11001021221. The reversal of 11001021217 is 71212010011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5970807441 + 5030213776 = 77271^2 + 70924^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001021217 is a prime.
It is a super-2 number, since 2×110010212172 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11001021217.
It is not a weakly prime, because it can be changed into another prime (11001021287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500510608 + 5500510609.
It is an arithmetic number, because the mean of its divisors is an integer number (5500510609).
Almost surely, 211001021217 is an apocalyptic number.
It is an amenable number.
11001021217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001021217 is an equidigital number, since it uses as much as digits as its factorization.
11001021217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 11001021217 its reverse (71212010011), we get a palindrome (82213031228).
The spelling of 11001021217 in words is "eleven billion, one million, twenty-one thousand, two hundred seventeen".
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