Base | Representation |
---|---|
bin | 11001000000110110111111… |
… | …000001001001100100000110 |
3 | 112102111212120010121021002112 |
4 | 121000312333001021210012 |
5 | 103404401343214231042 |
6 | 1025545553354141022 |
7 | 32112655235122325 |
oct | 3100667701114406 |
9 | 472455503537075 |
10 | 110010202102022 |
11 | 32064079143472 |
12 | 1040886a121772 |
13 | 494cbc0b00911 |
14 | 1d24744c720bc |
15 | cab9401e2982 |
hex | 640dbf049906 |
110010202102022 has 4 divisors (see below), whose sum is σ = 165015303153036. Its totient is φ = 55005101051010.
The previous prime is 110010202101949. The next prime is 110010202102067. The reversal of 110010202102022 is 220201202010011.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1100102021020223 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110010202101988 and 110010202102006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27502550525504 + ... + 27502550525507.
It is an arithmetic number, because the mean of its divisors is an integer number (41253825788259).
Almost surely, 2110010202102022 is an apocalyptic number.
110010202102022 is a deficient number, since it is larger than the sum of its proper divisors (55005101051014).
110010202102022 is an equidigital number, since it uses as much as digits as its factorization.
110010202102022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55005101051013.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 110010202102022 its reverse (220201202010011), we get a palindrome (330211404112033).
The spelling of 110010202102022 in words is "one hundred ten trillion, ten billion, two hundred two million, one hundred two thousand, twenty-two".
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