11001012131 has 2 divisors, whose sum is σ = 11001012132. Its totient is φ = 11001012130.

The previous prime is 11001012109. The next prime is 11001012133. The reversal of 11001012131 is 13121010011.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (13121010011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001012131 is a prime.

It is a super-2 number, since 2×11001012131² (a number of 21 digits) contains 22 as substring.

Together with 11001012133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11001012133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500506065 + 5500506066.

It is an arithmetic number, because the mean of its divisors is an integer number (5500506066).

Almost surely, 2^11001012131 is an apocalyptic number.

11001012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001012131 is an equidigital number, since it uses as much as digits as its factorization.

11001012131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11001012131 its reverse (13121010011), we get a palindrome (24122022142).

The spelling of 11001012131 in words is "eleven billion, one million, twelve thousand, one hundred thirty-one".