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110002313002 = 255001156501
BaseRepresentation
bin110011001110010100…
…1100001011100101010
3101111221020202111012211
41212130221201130222
53300241043004002
6122311231155334
710642650142621
oct1463451413452
9344836674184
10110002313002
114271948a98a
121939b675b4a
13a4b0b2994a
1454776266b8
152cdc402dd7
hex199ca6172a

110002313002 has 4 divisors (see below), whose sum is σ = 165003469506. Its totient is φ = 55001156500.

The previous prime is 110002312951. The next prime is 110002313011. The reversal of 110002313002 is 200313200011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 56373479761 + 53628833241 = 237431^2 + 231579^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500578249 + ... + 27500578252.

Almost surely, 2110002313002 is an apocalyptic number.

110002313002 is a deficient number, since it is larger than the sum of its proper divisors (55001156504).

110002313002 is an equidigital number, since it uses as much as digits as its factorization.

110002313002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55001156503.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 110002313002 its reverse (200313200011), we get a palindrome (310315513013).

It can be divided in two parts, 1100023 and 13002, that added together give a square (1113025 = 10552).

The spelling of 110002313002 in words is "one hundred ten billion, two million, three hundred thirteen thousand, two".

Divisors: 1 2 55001156501 110002313002