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10993433 = 118312041
BaseRepresentation
bin101001111011…
…111100011001
3202200112011012
4221323330121
510303242213
61031343305
7162304553
oct51737431
922615135
1010993433
116229590
123821b35
13237bab9
1416624d3
15e724a8
hexa7bf19

10993433 has 8 divisors (see below), whose sum is σ = 12138336. Its totient is φ = 9872800.

The previous prime is 10993421. The next prime is 10993439. The reversal of 10993433 is 33439901.

10993433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10993433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10993433.

It is not an unprimeable number, because it can be changed into a prime (10993439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5108 + ... + 6933.

It is an arithmetic number, because the mean of its divisors is an integer number (1517292).

Almost surely, 210993433 is an apocalyptic number.

It is an amenable number.

10993433 is a deficient number, since it is larger than the sum of its proper divisors (1144903).

10993433 is a wasteful number, since it uses less digits than its factorization.

10993433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12135.

The product of its (nonzero) digits is 8748, while the sum is 32.

The square root of 10993433 is about 3315.6346300520. The cubic root of 10993433 is about 222.3537430430.

The spelling of 10993433 in words is "ten million, nine hundred ninety-three thousand, four hundred thirty-three".

Divisors: 1 11 83 913 12041 132451 999403 10993433