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1082125147 = 13917534441
BaseRepresentation
bin100000001111111…
…1110101101011011
32210102012122122011
41000133332231123
54204011001042
6255213410351
735546624545
oct10037765533
92712178564
101082125147
11505916704
122624999b7
1314326294c
14a3a08695
1565004a17
hex407feb5b

1082125147 has 8 divisors (see below), whose sum is σ = 1090777520. Its totient is φ = 1073485440.

The previous prime is 1082125139. The next prime is 1082125151. The reversal of 1082125147 is 7415212801.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1082125147 - 23 = 1082125139 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1082125127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 241447 + ... + 245887.

It is an arithmetic number, because the mean of its divisors is an integer number (136347190).

Almost surely, 21082125147 is an apocalyptic number.

1082125147 is a deficient number, since it is larger than the sum of its proper divisors (8652373).

1082125147 is a wasteful number, since it uses less digits than its factorization.

1082125147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6333.

The product of its (nonzero) digits is 4480, while the sum is 31.

The square root of 1082125147 is about 32895.6706421985. The cubic root of 1082125147 is about 1026.6580808417.

Adding to 1082125147 its reverse (7415212801), we get a palindrome (8497337948).

The spelling of 1082125147 in words is "one billion, eighty-two million, one hundred twenty-five thousand, one hundred forty-seven".

Divisors: 1 139 1753 4441 243667 617299 7785073 1082125147