10434314121133 has 4 divisors (see below), whose sum is σ = 11924930424160. Its totient is φ = 8943697818108.

The previous prime is 10434314121097. The next prime is 10434314121173. The reversal of 10434314121133 is 33112141343401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10434314121133 is a prime.

It is a super-2 number, since 2×10434314121133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10434314121095 and 10434314121104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10434314121173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 745308151503 + ... + 745308151516.

It is an arithmetic number, because the mean of its divisors is an integer number (2981232606040).

Almost surely, 2^{10434314121133} is an apocalyptic number.

It is an amenable number.

10434314121133 is a deficient number, since it is larger than the sum of its proper divisors (1490616303027).

10434314121133 is an equidigital number, since it uses as much as digits as its factorization.

10434314121133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1490616303026.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 10434314121133 its reverse (33112141343401), we get a palindrome (43546455464534).

The spelling of 10434314121133 in words is "ten trillion, four hundred thirty-four billion, three hundred fourteen million, one hundred twenty-one thousand, one hundred thirty-three".