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10364141162213 is a prime number
BaseRepresentation
bin1001011011010001011011…
…1100111100111011100101
31100200210122211001220220222
42112310112330330323211
52324301230114142323
634013115401534125
72116533036221606
oct226642674747345
940623584056828
1010364141162213
113336453547893
1211b4781aa4345
135a244665c047
1427b8acb01dad
1512e8dd6b09c8
hex96d16f3cee5

10364141162213 has 2 divisors, whose sum is σ = 10364141162214. Its totient is φ = 10364141162212.

The previous prime is 10364141162201. The next prime is 10364141162227. The reversal of 10364141162213 is 31226114146301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10323356148004 + 40785014209 = 3212998^2 + 201953^2 .

It is a cyclic number.

It is not a de Polignac number, because 10364141162213 - 214 = 10364141145829 is a prime.

It is a super-3 number, since 3×103641411622133 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10364141162273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5182070581106 + 5182070581107.

It is an arithmetic number, because the mean of its divisors is an integer number (5182070581107).

Almost surely, 210364141162213 is an apocalyptic number.

It is an amenable number.

10364141162213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10364141162213 is an equidigital number, since it uses as much as digits as its factorization.

10364141162213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 10364141162213 in words is "ten trillion, three hundred sixty-four billion, one hundred forty-one million, one hundred sixty-two thousand, two hundred thirteen".