Base | Representation |
---|---|
bin | 10111011111101010100000… |
… | …001010011111000000000011 |
3 | 111112212100101202212210211101 |
4 | 113133222200022133000003 |
5 | 102020433402114411042 |
6 | 1003433335533555231 |
7 | 30523263522462334 |
oct | 2737524012370003 |
9 | 445770352783741 |
10 | 103331010310147 |
11 | 2aa19487539144 |
12 | b70a2aa345b17 |
13 | 45870c3276799 |
14 | 1b7336752828b |
15 | be2d23d676b7 |
hex | 5dfaa029f003 |
103331010310147 has 2 divisors, whose sum is σ = 103331010310148. Its totient is φ = 103331010310146.
The previous prime is 103331010310139. The next prime is 103331010310291. The reversal of 103331010310147 is 741013010133301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103331010310147 - 23 = 103331010310139 is a prime.
It is a super-2 number, since 2×1033310103101472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103331016310147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51665505155073 + 51665505155074.
It is an arithmetic number, because the mean of its divisors is an integer number (51665505155074).
Almost surely, 2103331010310147 is an apocalyptic number.
103331010310147 is a deficient number, since it is larger than the sum of its proper divisors (1).
103331010310147 is an equidigital number, since it uses as much as digits as its factorization.
103331010310147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 103331010310147 its reverse (741013010133301), we get a palindrome (844344020443448).
The spelling of 103331010310147 in words is "one hundred three trillion, three hundred thirty-one billion, ten million, three hundred ten thousand, one hundred forty-seven".
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