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103230450551 = 110393590617
BaseRepresentation
bin110000000100100000…
…0111010101101110111
3100212110022022020022102
41200021000322231313
53142403443404201
6115231242452315
710313101231454
oct1401100725567
9325408266272
10103230450551
113a863997448
121800b80409b
139971b80347
144dd40d482b
152a42b5026b
hex180903ab77

103230450551 has 4 divisors (see below), whose sum is σ = 103324042272. Its totient is φ = 103136858832.

The previous prime is 103230450541. The next prime is 103230450559. The reversal of 103230450551 is 155054032301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103230450551 - 210 = 103230449527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103230450559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46794206 + ... + 46796411.

It is an arithmetic number, because the mean of its divisors is an integer number (25831010568).

Almost surely, 2103230450551 is an apocalyptic number.

103230450551 is a deficient number, since it is larger than the sum of its proper divisors (93591721).

103230450551 is an equidigital number, since it uses as much as digits as its factorization.

103230450551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93591720.

The product of its (nonzero) digits is 9000, while the sum is 29.

Adding to 103230450551 its reverse (155054032301), we get a palindrome (258284482852).

The spelling of 103230450551 in words is "one hundred three billion, two hundred thirty million, four hundred fifty thousand, five hundred fifty-one".

Divisors: 1 1103 93590617 103230450551