Base | Representation |
---|---|
bin | 10111011100111101011101… |
… | …000110001000101100100001 |
3 | 111112012120210102211102012121 |
4 | 113130331131012020230201 |
5 | 102004412333041044014 |
6 | 1003212130150224241 |
7 | 30503665150620421 |
oct | 2734753506105441 |
9 | 445176712742177 |
10 | 103145201503009 |
11 | 2a9576a8293206 |
12 | b69a293355081 |
13 | 4572721058b63 |
14 | 1b6837c08c481 |
15 | bdd09b6e1124 |
hex | 5dcf5d188b21 |
103145201503009 has 2 divisors, whose sum is σ = 103145201503010. Its totient is φ = 103145201503008.
The previous prime is 103145201502991. The next prime is 103145201503021. The reversal of 103145201503009 is 900305102541301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75857950864609 + 27287250638400 = 8709647^2 + 5223720^2 .
It is a cyclic number.
It is not a de Polignac number, because 103145201503009 - 231 = 103143054019361 is a prime.
It is not a weakly prime, because it can be changed into another prime (103145201503079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51572600751504 + 51572600751505.
It is an arithmetic number, because the mean of its divisors is an integer number (51572600751505).
Almost surely, 2103145201503009 is an apocalyptic number.
It is an amenable number.
103145201503009 is a deficient number, since it is larger than the sum of its proper divisors (1).
103145201503009 is an equidigital number, since it uses as much as digits as its factorization.
103145201503009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 103145201503009 in words is "one hundred three trillion, one hundred forty-five billion, two hundred one million, five hundred three thousand, nine".
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