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103131100343 is a prime number
BaseRepresentation
bin110000000001100010…
…1111011010010110111
3100212012101100201110002
41200003011323102313
53142203030202333
6115213333221515
710310453613635
oct1400305732267
9325171321402
10103131100343
113a8128aa137
1217ba249189b
13995740653b
144dc4c32355
152a390780e8
hex180317b4b7

103131100343 has 2 divisors, whose sum is σ = 103131100344. Its totient is φ = 103131100342.

The previous prime is 103131100307. The next prime is 103131100363. The reversal of 103131100343 is 343001131301.

It is an a-pointer prime, because the next prime (103131100363) can be obtained adding 103131100343 to its sum of digits (20).

It is a strong prime.

It is an emirp because it is prime and its reverse (343001131301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103131100343 - 216 = 103131034807 is a prime.

It is a super-3 number, since 3×1031311003433 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103131100363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565550171 + 51565550172.

It is an arithmetic number, because the mean of its divisors is an integer number (51565550172).

Almost surely, 2103131100343 is an apocalyptic number.

103131100343 is a deficient number, since it is larger than the sum of its proper divisors (1).

103131100343 is an equidigital number, since it uses as much as digits as its factorization.

103131100343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 103131100343 its reverse (343001131301), we get a palindrome (446132231644).

The spelling of 103131100343 in words is "one hundred three billion, one hundred thirty-one million, one hundred thousand, three hundred forty-three".