Base | Representation |
---|---|
bin | 110000000001100010… |
… | …1111011010010110111 |
3 | 100212012101100201110002 |
4 | 1200003011323102313 |
5 | 3142203030202333 |
6 | 115213333221515 |
7 | 10310453613635 |
oct | 1400305732267 |
9 | 325171321402 |
10 | 103131100343 |
11 | 3a8128aa137 |
12 | 17ba249189b |
13 | 995740653b |
14 | 4dc4c32355 |
15 | 2a390780e8 |
hex | 180317b4b7 |
103131100343 has 2 divisors, whose sum is σ = 103131100344. Its totient is φ = 103131100342.
The previous prime is 103131100307. The next prime is 103131100363. The reversal of 103131100343 is 343001131301.
It is an a-pointer prime, because the next prime (103131100363) can be obtained adding 103131100343 to its sum of digits (20).
It is a strong prime.
It is an emirp because it is prime and its reverse (343001131301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103131100343 - 216 = 103131034807 is a prime.
It is a super-3 number, since 3×1031311003433 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103131100363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565550171 + 51565550172.
It is an arithmetic number, because the mean of its divisors is an integer number (51565550172).
Almost surely, 2103131100343 is an apocalyptic number.
103131100343 is a deficient number, since it is larger than the sum of its proper divisors (1).
103131100343 is an equidigital number, since it uses as much as digits as its factorization.
103131100343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 103131100343 its reverse (343001131301), we get a palindrome (446132231644).
The spelling of 103131100343 in words is "one hundred three billion, one hundred thirty-one million, one hundred thousand, three hundred forty-three".
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