Base | Representation |
---|---|
bin | 110000000001010001… |
… | …1101001001000000111 |
3 | 100212011202110010011200 |
4 | 1200002203221020013 |
5 | 3142143230104111 |
6 | 115212412433543 |
7 | 10310314332600 |
oct | 1400243511007 |
9 | 325152403150 |
10 | 103122113031 |
11 | 3a808820903 |
12 | 17b9b4788b3 |
13 | 99555aa8c2 |
14 | 4dc3972da7 |
15 | 2a383a0256 |
hex | 18028e9207 |
103122113031 has 36 divisors (see below), whose sum is σ = 173295885672. Its totient is φ = 58919210784.
The previous prime is 103122113009. The next prime is 103122113053. The reversal of 103122113031 is 130311221301.
It is an interprime number because it is at equal distance from previous prime (103122113009) and next prime (103122113053).
It is not a de Polignac number, because 103122113031 - 210 = 103122112007 is a prime.
It is a super-2 number, since 2×1031221130312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103122112995 and 103122113013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103122113531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 6517576 + ... + 6533378.
It is an arithmetic number, because the mean of its divisors is an integer number (4813774602).
Almost surely, 2103122113031 is an apocalyptic number.
103122113031 is a deficient number, since it is larger than the sum of its proper divisors (70173772641).
103122113031 is a wasteful number, since it uses less digits than its factorization.
103122113031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30620 (or 30610 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 103122113031 its reverse (130311221301), we get a palindrome (233433334332).
It can be divided in two parts, 103122 and 113031, that added together give a triangular number (216153 = T657).
The spelling of 103122113031 in words is "one hundred three billion, one hundred twenty-two million, one hundred thirteen thousand, thirty-one".
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