Base | Representation |
---|---|
bin | 10111001110001110110111… |
… | …101111111100110110100011 |
3 | 111101121211102001100201002112 |
4 | 113032032313233330312203 |
5 | 101341322102143212011 |
6 | 1001115145243505535 |
7 | 30340605452122301 |
oct | 2716166757746643 |
9 | 441554361321075 |
10 | 102133110132131 |
11 | 2a5a7455079421 |
12 | b5560b7b282ab |
13 | 44cb159a168c0 |
14 | 1b313a9c41271 |
15 | bc1ab36ab58b |
hex | 5ce3b7bfcda3 |
102133110132131 has 4 divisors (see below), whose sum is σ = 109989503219232. Its totient is φ = 94276717045032.
The previous prime is 102133110132101. The next prime is 102133110132133. The reversal of 102133110132131 is 131231011331201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 102133110132131 - 214 = 102133110115747 is a prime.
It is a super-3 number, since 3×1021331101321313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 102133110132097 and 102133110132106.
It is not an unprimeable number, because it can be changed into a prime (102133110132133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3928196543531 + ... + 3928196543556.
It is an arithmetic number, because the mean of its divisors is an integer number (27497375804808).
Almost surely, 2102133110132131 is an apocalyptic number.
102133110132131 is a deficient number, since it is larger than the sum of its proper divisors (7856393087101).
102133110132131 is an equidigital number, since it uses as much as digits as its factorization.
102133110132131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7856393087100.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 102133110132131 its reverse (131231011331201), we get a palindrome (233364121463332).
The spelling of 102133110132131 in words is "one hundred two trillion, one hundred thirty-three billion, one hundred ten million, one hundred thirty-two thousand, one hundred thirty-one".
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