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102015250038817 is a prime number
BaseRepresentation
bin10111001100100001000110…
…101111011000000000100001
3111101012120012011210121201021
4113030201012233120000201
5101332404213002220232
61000545054153005441
730326233665633013
oct2714410657300041
9441176164717637
10102015250038817
112a561474129925
12b5372a49b3881
1344bccc5c8060b
141b297c8bb21b3
15bbd9b6502397
hex5cc846bd8021

102015250038817 has 2 divisors, whose sum is σ = 102015250038818. Its totient is φ = 102015250038816.

The previous prime is 102015250038799. The next prime is 102015250038827. The reversal of 102015250038817 is 718830052510201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64334018680801 + 37681231358016 = 8020849^2 + 6138504^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102015250038817 is a prime.

It is a super-2 number, since 2×1020152500388172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102015250038827) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51007625019408 + 51007625019409.

It is an arithmetic number, because the mean of its divisors is an integer number (51007625019409).

Almost surely, 2102015250038817 is an apocalyptic number.

It is an amenable number.

102015250038817 is a deficient number, since it is larger than the sum of its proper divisors (1).

102015250038817 is an equidigital number, since it uses as much as digits as its factorization.

102015250038817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 43.

The spelling of 102015250038817 in words is "one hundred two trillion, fifteen billion, two hundred fifty million, thirty-eight thousand, eight hundred seventeen".