Base | Representation |
---|---|
bin | 1001001111001000010011… |
… | …0000100001101110011110 |
3 | 1022221212012100100221101021 |
4 | 2103302010300201232132 |
5 | 2312342011140020220 |
6 | 33333215220434354 |
7 | 2065466333502331 |
oct | 223620460415636 |
9 | 38855170327337 |
10 | 10155530001310 |
11 | 3265a32a27a91 |
12 | 11802625489ba |
13 | 58887c2c40b5 |
14 | 27175d106618 |
15 | 12927e26b4aa |
hex | 93c84c21b9e |
10155530001310 has 8 divisors (see below), whose sum is σ = 18279954002376. Its totient is φ = 4062212000520.
The previous prime is 10155530001307. The next prime is 10155530001439. The reversal of 10155530001310 is 1310003555101.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×101555300013102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507776500056 + ... + 507776500075.
It is an arithmetic number, because the mean of its divisors is an integer number (2284994250297).
Almost surely, 210155530001310 is an apocalyptic number.
10155530001310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10155530001310 is a deficient number, since it is larger than the sum of its proper divisors (8124424001066).
10155530001310 is a wasteful number, since it uses less digits than its factorization.
10155530001310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1015553000138.
The product of its (nonzero) digits is 1125, while the sum is 25.
Adding to 10155530001310 its reverse (1310003555101), we get a palindrome (11465533556411).
The spelling of 10155530001310 in words is "ten trillion, one hundred fifty-five billion, five hundred thirty million, one thousand, three hundred ten".
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