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101543355031441 is a prime number
BaseRepresentation
bin10111000101101001100111…
…100110110001111110010001
3111022112110011000002110102111
4113011221213212301332101
5101302141242342001231
6555544212345145321
730250156666355341
oct2705514746617621
9438473130073374
10101543355031441
112a39a32775a364
12b47b94818b241
1344876607216bb
141b10a2046cd21
15bb1597e744b1
hex5c5a679b1f91

101543355031441 has 2 divisors, whose sum is σ = 101543355031442. Its totient is φ = 101543355031440.

The previous prime is 101543355031411. The next prime is 101543355031507. The reversal of 101543355031441 is 144130553345101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94838771790400 + 6704583241041 = 9738520^2 + 2589321^2 .

It is a cyclic number.

It is not a de Polignac number, because 101543355031441 - 235 = 101508995293073 is a prime.

It is a super-2 number, since 2×1015433550314412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101543355031394 and 101543355031403.

It is not a weakly prime, because it can be changed into another prime (101543355031411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50771677515720 + 50771677515721.

It is an arithmetic number, because the mean of its divisors is an integer number (50771677515721).

Almost surely, 2101543355031441 is an apocalyptic number.

It is an amenable number.

101543355031441 is a deficient number, since it is larger than the sum of its proper divisors (1).

101543355031441 is an equidigital number, since it uses as much as digits as its factorization.

101543355031441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 101543355031441 in words is "one hundred one trillion, five hundred forty-three billion, three hundred fifty-five million, thirty-one thousand, four hundred forty-one".