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101543354900441 is a prime number
BaseRepresentation
bin10111000101101001100111…
…100110010001111111011001
3111022112110010222211210201122
4113011221213212101333121
5101302141242323303231
6555544212342255025
730250156665301406
oct2705514746217731
9438473128753648
10101543354900441
112a39a32767a9a3
12b47b948127475
1344876606a6b9c
141b10a204372ad
15bb1597e4a77b
hex5c5a67991fd9

101543354900441 has 2 divisors, whose sum is σ = 101543354900442. Its totient is φ = 101543354900440.

The previous prime is 101543354900423. The next prime is 101543354900527. The reversal of 101543354900441 is 144009453345101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100658681094400 + 884673806041 = 10032880^2 + 940571^2 .

It is a cyclic number.

It is not a de Polignac number, because 101543354900441 - 210 = 101543354899417 is a prime.

It is a super-2 number, since 2×1015433549004412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101543354900392 and 101543354900401.

It is not a weakly prime, because it can be changed into another prime (101543354930441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50771677450220 + 50771677450221.

It is an arithmetic number, because the mean of its divisors is an integer number (50771677450221).

Almost surely, 2101543354900441 is an apocalyptic number.

It is an amenable number.

101543354900441 is a deficient number, since it is larger than the sum of its proper divisors (1).

101543354900441 is an equidigital number, since it uses as much as digits as its factorization.

101543354900441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 44.

The spelling of 101543354900441 in words is "one hundred one trillion, five hundred forty-three billion, three hundred fifty-four million, nine hundred thousand, four hundred forty-one".