1014113 has 2 divisors, whose sum is σ = 1014114. Its totient is φ = 1014112.

The previous prime is 1014089. The next prime is 1014121. The reversal of 1014113 is 3114101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1014049 + 64 = 1007^2 + 8^2 .

It is a cyclic number.

It is not a de Polignac number, because 1014113 - 2¹⁸ = 751969 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1014094 and 1014103.

It is not a weakly prime, because it can be changed into another prime (1014173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507056 + 507057.

It is an arithmetic number, because the mean of its divisors is an integer number (507057).

2^1014113 is an apocalyptic number.

It is an amenable number.

1014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014113 is an equidigital number, since it uses as much as digits as its factorization.

1014113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1014113 is about 1007.0317770557. The cubic root of 1014113 is about 100.4682374483.

Subtracting from 1014113 its product of nonzero digits (12), we obtain a palindrome (1014101).

Adding to 1014113 its reverse (3114101), we get a palindrome (4128214).

The spelling of 1014113 in words is "one million, fourteen thousand, one hundred thirteen".