10132023113 has 4 divisors (see below), whose sum is σ = 10194182928. Its totient is φ = 10069863300.

The previous prime is 10132023107. The next prime is 10132023133. The reversal of 10132023113 is 31132023101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31132023101 = 27437 ⋅1134673.

It is a cyclic number.

It is not a de Polignac number, because 10132023113 - 2³⁰ = 9058281289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10132023091 and 10132023100.

It is not an unprimeable number, because it can be changed into a prime (10132023133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31079663 + ... + 31079988.

It is an arithmetic number, because the mean of its divisors is an integer number (2548545732).

Almost surely, 2^10132023113 is an apocalyptic number.

It is an amenable number.

10132023113 is a deficient number, since it is larger than the sum of its proper divisors (62159815).

10132023113 is an equidigital number, since it uses as much as digits as its factorization.

10132023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62159814.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10132023113 its reverse (31132023101), we get a palindrome (41264046214).

The spelling of 10132023113 in words is "ten billion, one hundred thirty-two million, twenty-three thousand, one hundred thirteen".