Base | Representation |
---|---|
bin | 10010110111101111… |
… | …01010001000010011 |
3 | 222011001201220122121 |
4 | 21123313222020103 |
5 | 131222100023411 |
6 | 4353151515111 |
7 | 506030135026 |
oct | 113367521023 |
9 | 28131656577 |
10 | 10131251731 |
11 | 4329911417 |
12 | 1b68b28a97 |
13 | c55c53913 |
14 | 6c176b1bd |
15 | 3e4687571 |
hex | 25bdea213 |
10131251731 has 2 divisors, whose sum is σ = 10131251732. Its totient is φ = 10131251730.
The previous prime is 10131251707. The next prime is 10131251821. The reversal of 10131251731 is 13715213101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10131251731 - 219 = 10130727443 is a prime.
It is a super-2 number, since 2×101312517312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10131251696 and 10131251705.
It is not a weakly prime, because it can be changed into another prime (10131231731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065625865 + 5065625866.
It is an arithmetic number, because the mean of its divisors is an integer number (5065625866).
Almost surely, 210131251731 is an apocalyptic number.
10131251731 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131251731 is an equidigital number, since it uses as much as digits as its factorization.
10131251731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 630, while the sum is 25.
Adding to 10131251731 its reverse (13715213101), we get a palindrome (23846464832).
The spelling of 10131251731 in words is "ten billion, one hundred thirty-one million, two hundred fifty-one thousand, seven hundred thirty-one".
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