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10114928333 is a prime number
BaseRepresentation
bin10010110101110010…
…11000111011001101
3222002221000121011022
421122321120323031
5131203410201313
64351410003525
7505441320656
oct113271307315
928087017138
1010114928333
114320682404
121b635765a5
13c52759ac3
146bd51c52d
153e3010c08
hex25ae58ecd

10114928333 has 2 divisors, whose sum is σ = 10114928334. Its totient is φ = 10114928332.

The previous prime is 10114928323. The next prime is 10114928347. The reversal of 10114928333 is 33382941101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10114928329 + 4 = 100573^2 + 2^2 .

It is a cyclic number.

It is not a de Polignac number, because 10114928333 - 28 = 10114928077 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10114928293 and 10114928302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10114928323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057464166 + 5057464167.

It is an arithmetic number, because the mean of its divisors is an integer number (5057464167).

Almost surely, 210114928333 is an apocalyptic number.

It is an amenable number.

10114928333 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114928333 is an equidigital number, since it uses as much as digits as its factorization.

10114928333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 10114928333 in words is "ten billion, one hundred fourteen million, nine hundred twenty-eight thousand, three hundred thirty-three".