10114113 has 4 divisors (see below), whose sum is σ = 13485488. Its totient is φ = 6742740.

The previous prime is 10114081. The next prime is 10114129. The reversal of 10114113 is 31141101.

10114113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31141101 = 3 ⋅10380367.

It is not a de Polignac number, because 10114113 - 2⁵ = 10114081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10114183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685683 + ... + 1685688.

It is an arithmetic number, because the mean of its divisors is an integer number (3371372).

Almost surely, 2^10114113 is an apocalyptic number.

It is an amenable number.

10114113 is a deficient number, since it is larger than the sum of its proper divisors (3371375).

10114113 is an equidigital number, since it uses as much as digits as its factorization.

10114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3371374.

The product of its (nonzero) digits is 12, while the sum is 12.

The square root of 10114113 is about 3180.2693282173. The cubic root of 10114113 is about 216.2598681275.

Adding to 10114113 its reverse (31141101), we get a palindrome (41255214).

The spelling of 10114113 in words is "ten million, one hundred fourteen thousand, one hundred thirteen".