Base | Representation |
---|---|
bin | 1001001100011110101011… |
… | …1101101111001100110011 |
3 | 1022210111200021211022120121 |
4 | 2103013222331233030303 |
5 | 2311120240011201042 |
6 | 33300245300551111 |
7 | 2062265140642603 |
oct | 223075275571463 |
9 | 38714607738517 |
10 | 10110000100147 |
11 | 32486995423a2 |
12 | 11734766b2497 |
13 | 5844a468bb8c |
14 | 26d48033ac03 |
15 | 127eb705a367 |
hex | 931eaf6f333 |
10110000100147 has 2 divisors, whose sum is σ = 10110000100148. Its totient is φ = 10110000100146.
The previous prime is 10110000100009. The next prime is 10110000100171. The reversal of 10110000100147 is 74100100001101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10110000100147 - 215 = 10110000067379 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10110000100147.
It is not a weakly prime, because it can be changed into another prime (10110000160147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055000050073 + 5055000050074.
It is an arithmetic number, because the mean of its divisors is an integer number (5055000050074).
Almost surely, 210110000100147 is an apocalyptic number.
10110000100147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110000100147 is an equidigital number, since it uses as much as digits as its factorization.
10110000100147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 10110000100147 its reverse (74100100001101), we get a palindrome (84210100101248).
The spelling of 10110000100147 in words is "ten trillion, one hundred ten billion, one hundred thousand, one hundred forty-seven".
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