Base | Representation |
---|---|
bin | 11101011001111010000… |
… | …10110010000100100101 |
3 | 10120120212102200201121012 |
4 | 32230331002302010211 |
5 | 113023134403012432 |
6 | 2052051111432005 |
7 | 132665126443022 |
oct | 16547502620445 |
9 | 3516772621535 |
10 | 1010341454117 |
11 | 35a535458496 |
12 | 143989385605 |
13 | 74375939468 |
14 | 36c87a90549 |
15 | 1b4345c0cb2 |
hex | eb3d0b2125 |
1010341454117 has 2 divisors, whose sum is σ = 1010341454118. Its totient is φ = 1010341454116.
The previous prime is 1010341454099. The next prime is 1010341454159. The reversal of 1010341454117 is 7114541430101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 597542914081 + 412798540036 = 773009^2 + 642494^2 .
It is a cyclic number.
It is not a de Polignac number, because 1010341454117 - 26 = 1010341454053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1010341454417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505170727058 + 505170727059.
It is an arithmetic number, because the mean of its divisors is an integer number (505170727059).
Almost surely, 21010341454117 is an apocalyptic number.
It is an amenable number.
1010341454117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010341454117 is an equidigital number, since it uses as much as digits as its factorization.
1010341454117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 32.
Adding to 1010341454117 its reverse (7114541430101), we get a palindrome (8124882884218).
The spelling of 1010341454117 in words is "one trillion, ten billion, three hundred forty-one million, four hundred fifty-four thousand, one hundred seventeen".
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