Base | Representation |
---|---|
bin | 10110111101111001000000… |
… | …011001000000011111111001 |
3 | 111020122110210000111101202001 |
4 | 112331321000121000133321 |
5 | 101214422212004233133 |
6 | 554455224204541001 |
7 | 30163511652315331 |
oct | 2675710031003771 |
9 | 436573700441661 |
10 | 101010121164793 |
11 | 2a204174083a75 |
12 | b3b4531251761 |
13 | 44492a1243099 |
14 | 1ad2cb751c0c1 |
15 | ba278987987d |
hex | 5bde406407f9 |
101010121164793 has 2 divisors, whose sum is σ = 101010121164794. Its totient is φ = 101010121164792.
The previous prime is 101010121164713. The next prime is 101010121164877. The reversal of 101010121164793 is 397461121010101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72080643361024 + 28929477803769 = 8490032^2 + 5378613^2 .
It is a cyclic number.
It is not a de Polignac number, because 101010121164793 - 237 = 100872682211321 is a prime.
It is not a weakly prime, because it can be changed into another prime (101010121164713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505060582396 + 50505060582397.
It is an arithmetic number, because the mean of its divisors is an integer number (50505060582397).
Almost surely, 2101010121164793 is an apocalyptic number.
It is an amenable number.
101010121164793 is a deficient number, since it is larger than the sum of its proper divisors (1).
101010121164793 is an equidigital number, since it uses as much as digits as its factorization.
101010121164793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 37.
Adding to 101010121164793 its reverse (397461121010101), we get a palindrome (498471242174894).
The spelling of 101010121164793 in words is "one hundred one trillion, ten billion, one hundred twenty-one million, one hundred sixty-four thousand, seven hundred ninety-three".
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