Base | Representation |
---|---|
bin | 101110110100011101… |
… | …0110110000101100001 |
3 | 100121112010020000112111 |
4 | 1131220322312011201 |
5 | 3121403343113121 |
6 | 114104533355321 |
7 | 10156405120123 |
oct | 1355072660541 |
9 | 317463200474 |
10 | 100544504161 |
11 | 3970582a142 |
12 | 175a0198b41 |
13 | 963457755a |
14 | 4c1b4bd213 |
15 | 2936e442e1 |
hex | 1768eb6161 |
100544504161 has 2 divisors, whose sum is σ = 100544504162. Its totient is φ = 100544504160.
The previous prime is 100544504119. The next prime is 100544504219. The reversal of 100544504161 is 161405445001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98646246400 + 1898257761 = 314080^2 + 43569^2 .
It is a cyclic number.
It is not a de Polignac number, because 100544504161 - 223 = 100536115553 is a prime.
It is not a weakly prime, because it can be changed into another prime (100544534161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50272252080 + 50272252081.
It is an arithmetic number, because the mean of its divisors is an integer number (50272252081).
Almost surely, 2100544504161 is an apocalyptic number.
It is an amenable number.
100544504161 is a deficient number, since it is larger than the sum of its proper divisors (1).
100544504161 is an equidigital number, since it uses as much as digits as its factorization.
100544504161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 100544504161 its reverse (161405445001), we get a palindrome (261949949162).
The spelling of 100544504161 in words is "one hundred billion, five hundred forty-four million, five hundred four thousand, one hundred sixty-one".
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