Base | Representation |
---|---|
bin | 11101001010111100111… |
… | …10000111011100111001 |
3 | 10112211010212111010012012 |
4 | 32211132132013130321 |
5 | 112410213424124423 |
6 | 2044242251455305 |
7 | 132262143155000 |
oct | 16453636073471 |
9 | 3484125433165 |
10 | 1002312333113 |
11 | 3570951aaaa3 |
12 | 142308457535 |
13 | 7369636b4a0 |
14 | 367255a5c37 |
15 | 1b114772078 |
hex | e95e787739 |
1002312333113 has 32 divisors (see below), whose sum is σ = 1259138496000. Its totient is φ = 792819413568.
The previous prime is 1002312333107. The next prime is 1002312333199. The reversal of 1002312333113 is 3113332132001.
It is not a de Polignac number, because 1002312333113 - 210 = 1002312332089 is a prime.
It is a super-2 number, since 2×10023123331132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1002312333313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17196023 + ... + 17254211.
It is an arithmetic number, because the mean of its divisors is an integer number (39348078000).
Almost surely, 21002312333113 is an apocalyptic number.
1002312333113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1002312333113 is a deficient number, since it is larger than the sum of its proper divisors (256826162887).
1002312333113 is an equidigital number, since it uses as much as digits as its factorization.
1002312333113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62086 (or 62072 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1002312333113 its reverse (3113332132001), we get a palindrome (4115644465114).
The spelling of 1002312333113 in words is "one trillion, two billion, three hundred twelve million, three hundred thirty-three thousand, one hundred thirteen".
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