Base | Representation |
---|---|
bin | 10110110001001010000110… |
… | …011001001111110000001111 |
3 | 111010112211020211202210001001 |
4 | 112301022012121033300033 |
5 | 101111103212302212030 |
6 | 552545235022401131 |
7 | 30043344451602451 |
oct | 2661120631176017 |
9 | 433484224683031 |
10 | 100135122304015 |
11 | 299a7081029107 |
12 | b292a35a301a7 |
13 | 43b49172cbba6 |
14 | 1aa27cc6d82d1 |
15 | b89b27197cca |
hex | 5b128664fc0f |
100135122304015 has 16 divisors (see below), whose sum is σ = 121405175283168. Its totient is φ = 79279469899776.
The previous prime is 100135122304001. The next prime is 100135122304081. The reversal of 100135122304015 is 510403221531001.
It is a cyclic number.
It is not a de Polignac number, because 100135122304015 - 243 = 91339029281807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10336599 + ... + 17524711.
It is an arithmetic number, because the mean of its divisors is an integer number (7587823455198).
Almost surely, 2100135122304015 is an apocalyptic number.
100135122304015 is a deficient number, since it is larger than the sum of its proper divisors (21270052979153).
100135122304015 is an equidigital number, since it uses as much as digits as its factorization.
100135122304015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7216938.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 100135122304015 its reverse (510403221531001), we get a palindrome (610538343835016).
The spelling of 100135122304015 in words is "one hundred trillion, one hundred thirty-five billion, one hundred twenty-two million, three hundred four thousand, fifteen".
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