Base | Representation |
---|---|
bin | 10110101111110011111000… |
… | …000011110011011111100001 |
3 | 111010012222021121211201002020 |
4 | 112233303320003303133201 |
5 | 101103044110220132340 |
6 | 552434524114412053 |
7 | 30033556255211400 |
oct | 2657637003633741 |
9 | 433188247751066 |
10 | 100042540005345 |
11 | 29970891802893 |
12 | b278ab8291029 |
13 | 43a8c814c3a42 |
14 | 1a9c128885637 |
15 | b875092859d0 |
hex | 5afcf80f37e1 |
100042540005345 has 96 divisors (see below), whose sum is σ = 193389801333120. Its totient is φ = 43980781824000.
The previous prime is 100042540005301. The next prime is 100042540005371. The reversal of 100042540005345 is 543500045240001.
It is not a de Polignac number, because 100042540005345 - 236 = 99973820528609 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3999592 + ... + 14699721.
It is an arithmetic number, because the mean of its divisors is an integer number (2014477097220).
Almost surely, 2100042540005345 is an apocalyptic number.
100042540005345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
100042540005345 is a deficient number, since it is larger than the sum of its proper divisors (93347261327775).
100042540005345 is a wasteful number, since it uses less digits than its factorization.
100042540005345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18699615 (or 18699608 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 33.
Adding to 100042540005345 its reverse (543500045240001), we get a palindrome (643542585245346).
The spelling of 100042540005345 in words is "one hundred trillion, forty-two billion, five hundred forty million, five thousand, three hundred forty-five".
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