13251401 has 4 divisors (see below), whose sum is σ = 13258704. Its totient is φ = 13244100.

The previous prime is 13251391. The next prime is 13251419. The reversal of 13251401 is 10415231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 10415231 = 2953 ⋅3527.

It is a cyclic number.

It is not a de Polignac number, because 13251401 - 2¹⁴ = 13235017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13251401.

It is not an unprimeable number, because it can be changed into a prime (13251421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1406 + ... + 5336.

It is an arithmetic number, because the mean of its divisors is an integer number (3314676).

Almost surely, 2^13251401 is an apocalyptic number.

It is an amenable number.

13251401 is a deficient number, since it is larger than the sum of its proper divisors (7303).

13251401 is an equidigital number, since it uses as much as digits as its factorization.

13251401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7302.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 13251401 is about 3640.2473817036. The cubic root of 13251401 is about 236.6395143970.

Adding to 13251401 its reverse (10415231), we get a palindrome (23666632).

The spelling of 13251401 in words is "thirteen million, two hundred fifty-one thousand, four hundred one".